$$f(x)=10*(6-x)*e^{(-0,05x^2+0,6x-1,75)}$$
$$f(x)=g(x)*h(x)$$
$$g(x)=10*(6-x)$$
$$g'(x)=-10$$
$$h(x)=e^{(-0,05x^2+0,6x-1,75)}$$
$$h'(x)=(-0,1x+0,6) e^{(-0,05x^2+0,6x-1,75)}$$
$$f'(x)=g(x)*h'(x)+g'(x)*h(x)$$
$$f'(x)=10*(6-x)(-0,1x+0,6) e^{(-0,05x^2+0,6x-1,75)}-10*e^{(-0,05x^2+0,6x-1,75)}$$
$$f'(x)=10*((6-x)(-0,1x+0,6)-1)*e^{(-0,05x^2+0,6x-1,75)}=0$$$$(6-x)(-0,1x+0,6)-1=0$$$$0,1x^2-1,2x+2,6=0$$$$x^2-12x+26=0$$$$x_1=6+ \sqrt{36-26} $$$$x_1=6+ \sqrt{10} ≈9,162$$$$x_2=6- \sqrt{10} ≈2,838$$