Variable i freistellen

Question

Wie bekomme ich die Variable i?

$-130+\frac{10}{(1+i)}+\frac{12}{(1+i)^{2}}=0$

Answer 1

Hi,

-130 + 10/(1+i) + 12/(1+i)² = 0   |*(1+i)²

-130(1+i)² + 10(1+i) + 12 = 0

-130i²-260i-130 + 10+10i + 12 = 0

-130i²-250i-108 = 0          |:(-130), dann pq-Formel

i_1,2 = -125/130 ± √(1585)/130

 

Grüße