Normalenvektor
[5, 0, 0] ⨯ [-5, -3, 6] = [0, -30, -15] = -15·[0, 2, 1]
Gleichungssystem
[0, 0, 0] + r·[5, 0, 0] + s·[0, 2, 1] = [5, 6, 0] + t·[-5, -3, 6] --> r = 0.6 ∧ s = 2.4 ∧ t = 0.4
Befestigungspunkte
[0, 0, 0] + 0.6·[5, 0, 0] = [3, 0, 0]
[5, 6, 0] + 0.4·[-5, -3, 6] = [3, 4.8, 2.4]
Länge des Stützbalkens
2.4·|[0, 2, 1]| = 2.4·√5 = 5.367