f(x) = a·x^2 + b·x + c
f(102) = 10609
f(105) = 11236
f(108) = 11881
10404·a + 102·b + c = 10609
11025·a + 105·b + c = 11236
11664·a + 108·b + c = 11881
Die Lösung lautet a = 1 ∧ b = 2 ∧ c = 1
f(x) = x^2 + 2·x + 1 = 12996
x = 113
Daher denke ich
113 = 12996
