Hallo Ninad,
2*5 = 10
\(\frac{3}{5}\) + \(\frac{2}{10}\) = \(\frac{3·2}{10}\) + \(\frac{2}{10}\) = \(\frac{3·2+2}{10}\)
genauso ist es hier:
(x+2) · (x+2) = (x+2)2
\(\frac{-2+x}{x+2}\) + \(\frac{2}{(x+2)^2}\) = \(\frac{(-2+x)·(x+2)}{(x+2)^2}\) +\(\frac{2}{(x+2)^2}\) = \(\frac{(-2+x)·(x+2) + 2}{(x+2)^2}\)
[ = \(\frac{x^2-2}{(x+2)^2}\) nach der 3. binomischen Formel ]
Gruß Wolfgang