f(x) = a·x^3 + b·x^2 + c·x + d
f'(x) = 3·a·x^2 + 2·b·x + c
f''(x) = 6·a·x + 2·b
f(2) = -2 --> 8·a + 4·b + 2·c + d = -4
f'(2) = 0 --> 12·a + 4·b + c = 0
f(1) = -2 --> a + b + c + d = -2
f''(1) = 0 --> 6·a + 2·b = 0
Löse das Gleichungssystem und erhalte: a = 1 ∧ b = -3 ∧ c = 0 ∧ d = 0
