f(x)=-\( \frac{6}{5} \)x+4
P(u|f(u))
f(u)=-\( \frac{6}{5} \)u+4
A=u*f(u) soll maximal werden.
A=u*(-\( \frac{6}{5} \)u+4)
A=-\( \frac{6}{5} \)u^2+4u
A´=-\( \frac{12}{5} \)u+4
-\( \frac{12}{5} \)u+4=0
\( \frac{12}{5} \)u=4
u=\( \frac{20}{12} \)=\( \frac{4}{3} \)
f(\( \frac{4}{3} \))=-\( \frac{6}{5} \)*\( \frac{4}{3} \)+4=\( \frac{12}{5} \)