Hallo,
wie kann man die partikuläre Lösung bestimmen?
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yp= \( \frac{-x}{225} \)\( e^{2x} \) - \( \frac{-x^2}{30} \)\( e^{2x} \)
Lösung: y=yh +yp
\( y(x)=C_{1} e^{2 x}+C_{3} e^{-4 x} \sin (3 x)+C_{2} e^{-4 x} \cos (3 x)-\frac{1}{30} e^{2 x} x^{2}-\frac{1}{225} e^{2 x} x \)