Hi,
e^{2x} = 5 |ln
2x = ln(5)
x = ln(5)/2
War hier gemeint:
3^{x-1} = 4^x
3^x/3 = 4^x |:3/x
1/3 = (4/3)^x |ln
ln(1/3) = x*ln(4/3) |:ln(4/3)
x = ln(1/3)/ln(4/3)
2 = log((x-3)^{65})
2 = 65*log(x-3) |:65
2/65 = log(x-3) |Annahme log = ln -> e-Funktion
e^{2/65} = x-3
x = e^{2/65}+3
6*3^x = 2^x |:3^x
6 = (2/3)^x |ln
ln(6) = x*ln(2/3) |:ln(2/3)
x = ln(6)/ln(2/3)
Grüße