Ganzrationale Funktion 3.Grades:
f(x) = ax3 + bx2 + cx + d
1.Ableitung:
f '(x) = 3ax2 + 2bx + c
f (-1) = 0 0 = a · (-1)3 + b · (-1)2 + c · (-1) + d <=> 0 = -a + b - c + d
f (0) = 2 2 = a · 03 + b · 02 + c · 0 + d <=> 2 = d
f (2) = 0 0 = a · 23 + b · 22 + c · 2 + d <=> 0 = 8a + 4b + 2c + d
f '(2) = 0 0 = 3 · a · 22 + 2 · b · 2 + c <=> 0 = 12a + 4b + c
a = 0,5
b = -1,5
c = 0
d = 2
f (x) = 0,5x3 -1,5 x2 + 2