x= eln x
n= 1/u .... also u=1/n . ... mit u->0 wenn n->oo
n* ( x1/n -1) ... -> .. [ eu * ln x -1 ] / u
etwas verallgemeinert : sei u in R ->
lim_(u->0) { [ eu * ln x -1 ] / u } ..... de l ' Hospital ->
lim_(u->0) { [ ln x * eu * ln x ] / 1 } = [ ln x * e0 * ln x ] / 1 = ln x