1/2 ln(2 e-z +1)= ln|x| +C1 | *2
ln(2 e-z +1)= 2(ln|x| +C1 ) | e hoch
2 e-z +1= e^{2(ln|x| +C1 )}
2 e-z +1= e^{2(ln|x|) } *e^{C}
e^{C} =C1
2 e-z +1= C1 *x2
2 e-z = C1 *x2 -1
e-z = (C1 *x2 -1)/2
------->Kehrwert
-------->
ez = 2/ (C1 *x2 -1) |ln(..)
z= ln (2/ (C1 *x2 -1))
Resubstitution:
z=y/x = ln (2/ (C1 *x2 -1))
y= x *ln (2/ (C1 *x2 -1))