a)
pa(x) = 20 + 10/5*x = 20 + 2*x
b)
pa(x) = pn(x)
20 + 2*x = -3*x + 150
x = 26
pa(x) = 20 + 2*26 = 72
c)
pa(x) = 20 + 2*x --> xa(p) = p/2 - 10
pn(x) = -3*x + 150 --> xn(p) = 50 - p/3
xn(60) - xa(60) = 10 --> Nachfrageüberhang von 10 ME
xa(100) - xn(100) = 23.33 --> Angebotsüberhang von 23.33 ME