f(x) = 0.25*x2 - 2
f'(x) = 0.5*x
Newton Formel
x_neu = x - f(x)/f'(x)
x_neu = x - (0.25*x2 - 2)/(0.5*x)
x0 = 5
x1 = 5 - (0.25*52 - 2)/(0.5*5) = 3.3
x2 = 3.3 - (0.25*3.32 - 2)/(0.5*3.3) = 2.862121212
x3 = 2.862121212 - (0.25*2.8621212122 - 2)/(0.5*2.862121212) = 2.828625455
x4 = 2.828625455 - (0.25*2.8286254552 - 2)/(0.5*2.828625455) = 2.828427131
x5 = 2.828427131 - (0.25*2.8284271312 - 2)/(0.5*2.828427131) = 2.828427131
Hier findet keine Änderung der Zahl mehr statt, weshalb ich dies als Näherung nehme.