4[x-(2x-3)]-3(2x+9)=46-[3(6-x)-4(7x+20)]

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3 Antworten

Ein anderes Problem?

Caramba · Answer 1 · 2017-09-01T08:24:17+0000

Lu · Answer 2 · 2017-09-01T10:02:15+0000

4[x-(2x-3)]-3(2x+9)=46-[3(6-x)-4(7x+20)]

4[x-2x+3]-(6x+27)=46-[18 - 3x -(28x+80)]

4[-x+3]- 6x -27=46- 18 + 3x + (28x+80)

-4x + 12 - 6x - 27 = 28 + 3x + 28x + 80

-10x - 15 = 108 + 31x

- 123 = 41x | : 41

-3 = x

Silvia · Answer 3 · 2017-09-01T10:04:02+0000

Hallo HH,

$$4\left[ x-\left( 2x-3 \right) \right] - 3\left( 2x+9 \right) = 46 - \left[ 3\left( 6-x \right)-4\left( 7x + 20 \right) \right]$$

$$4\left( x-2x+3 \right) - 3\left( 2x+9 \right) = 46 - \left[ 18 - 3x - 28x - 80\right]$$

$$4\left( -x+3 \right)-6x-27 = 46 - \left[ 18 - 3x - 28x - 80\right]$$

$$-4x+12-6x-27 = 46 - \left( -62-31x \right)$$

$$-10x-15=46 + 62+31x$$

$$-10x-15=108+31x$$

$$-41x =123$$

$$x=-3$$

Gruß, Silvia