$$ x^2 +7x = 26 \quad | -26 $$
$$ x^2+7x-26=0 $$
Anwenden der PQ Formel
$$ p=7 \quad q=-26 $$
$$ \frac{-p}{2}\pm \sqrt{\left(\frac{p}{2}\right)^2-q} $$
$$ \frac{-7}{2}\pm \sqrt{\left(\frac{7}{2}\right)^2-(-26)} $$
$$ x_1 = -9.6847... \quad x_2 = 2.6847 $$
~plot~ x^2+7x-26 ~plot~
Hope this helps!