Hi,
e^{3x}(e^x)^2 = √(e^{-8}/e^{2x})
e^{3x}e^{2x} = √e^{-2x-8}
e^{3x+2x} = e^{-x-4}
e^{5x} = e^{-x-4}
5x = -x-4 |+x
6x = -4
x = -2/3
ln(√(7^{12-x}) + 11ln(2) = 11ln(6)
ln(7(12-x)/2) + 11ln(2) = 11ln(2) + 11ln(3) |-11ln(2)
ln(7(12-x)/2) = 11ln(3)
(12-x)/2 ln(7) = 11ln(3)
6ln(7) - x/2*ln(7) = 11ln(3) |-11ln(3)+x/2ln(7)
x/2 ln(7) = 6ln(7) - 11ln(3)
x = 2(6ln(7)-11ln(3))/ln(7) ≈ -0,42
Alles klar?
Grüße