https://www.geogebra.org/m/upUZg79r
Die Eigenwerte
\(\small \left(\begin{array}{rrrr}\lambda=&-3&\left(\begin{array}{rr}\frac{8}{3}&\frac{8}{3}\\\frac{4}{3}&\frac{4}{3}\\\end{array}\right)&\left(\begin{array}{r}x1\\x2\\\end{array}\right) = 0\\\lambda=&1&\left(\begin{array}{rr}\frac{-4}{3}&\frac{8}{3}\\\frac{4}{3}&\frac{-8}{3}\\\end{array}\right)&\left(\begin{array}{r}x1\\x2\\\end{array}\right) = 0\\\end{array}\right) \)
führen auf die Eigenvektoren
\(\small \left(\begin{array}{r}x1\\x2\\\end{array}\right) = \left(\begin{array}{rr}-x2&2 \; x2\\x2&x2\\\end{array}\right) \)