c) \( A(0 \mid-1,5) ; B(-3 \mid 0) ; C(-1 \mid-2) \)
f(x)=a*(x+3)*(x-N)
f(0)=a*(0+3)*(0-N)=-3aN
1.)-3aN=-1,5 → aN=0,5 → a=\( \frac{0,5}{N} \)
f(-1)=\( \frac{0,5}{N} \)*(-1+3)*(-1-N)=\( \frac{1}{N} \)*(-1-N)
2.)\( \frac{1}{N} \)*(-1-N)=-2 →1+N=2N →N=1 a=\( \frac{0,5}{1} \)=0,5
f(x)=0,5*(x+3)*(x-1)