Gleichung dritten Grades mit folgenden Punkten \(g(-2) = 0\) \(g ' (-2) = - 5\)
\(g ' (2) = -9\) \(g(0) = 0\)
\(g(x)=a*[x*(x+2)*(x-N)]\)
\(g´(x)=a*[(x+2)*(x-N)+x*(x-N)+x*(x+2)]\)
\(g´(-2)=a*[4+2N]\)
\(a*[4+2N]=-5→a=-\frac{5}{4+2N}\)
\(g´(2)=-\frac{5}{4+2N}*[(2+2)*(2-N)+2*(2-N)+2*(2+2)\)]
\(\frac{5}{4+2N}*(20-6N)=9\)
\(N=\frac{4}{3}\)
\(a=-\frac{5}{4+2*\frac{4}{3}}=-\frac{3}{4}\)
\(g(x)=-\frac{3}{4}*x*(x+2)*(x-\frac{4}{3})\)