a) \( \frac{17}{2 x}+5 \frac{1}{2}-\frac{2}{3} \cdot\left(\frac{8}{x}-\frac{7,5}{6}\right)=\frac{13}{x}-3,5 \) mit \(x≠0\)
\( \frac{17}{2 x}+ \frac{11}{2}-\frac{2}{3} \cdot\left(\frac{8}{x}-\frac{7,5}{6}\right)=\frac{13}{x}-\frac{7}{2} \)
\( \frac{17}{2 x}+ \frac{11}{2}+\frac{7}{2} -\frac{2}{3} \cdot\left(\frac{8}{x}-\frac{7,5}{6}\right)=\frac{13}{x}\)
\( \frac{17}{2 x}+9 -\frac{2}{3} \cdot\left(\frac{8}{x}-\frac{7,5}{6}\right)=\frac{13}{x}\)
\( \frac{17}{2x} +9-\frac{16}{3x}+\frac{15}{18}=\frac{13}{x}\)
\( \frac{17}{2x} +\frac{54}{6}-\frac{16}{3x}+\frac{5}{6}=\frac{13}{x}\)
\( \frac{17}{2x} +\frac{59}{6}-\frac{16}{3x}=\frac{13}{x} |\cdot3x\)
\( \frac{51}{2} +\frac{59}{2}x-16=39 \)
\( \frac{51}{2} +\frac{59}{2}x=55 \)
\( 51 +59x=110 \)
\( x=1 \)
b) \( 2 \frac{1}{3} \cdot(5 x-8)-\frac{x+3}{2}=1 \frac{1}{2}+\frac{1}{3} \cdot x \)
\( \frac{7}{3} \cdot(5 x-8)-\frac{x+3}{2}= \frac{3}{2}+\frac{1}{3} \cdot x |\cdot 6 \)
\( 14\cdot(5 x-8)-3\cdot (x+3)= 9+2 \cdot x \)
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