\( D_{y}(45°)=\left(\begin{array}{ccc}0,5\sqrt{2} & 0 & 0,5\sqrt{2} \\ 0 & 1 & 0 \\ -0,5\sqrt{2} & 0 & 0,5\sqrt{2}\end{array}\right) \)
Also rechne
\( \left(\begin{array}{ccc}0,5\sqrt{2} & 0 & 0,5\sqrt{2} \\ 0 & 1 & 0 \\ -0,5\sqrt{2} & 0 & 0,5\sqrt{2}\end{array}\right) \cdot \left(\begin{array}{ccc}0,5\sqrt{2} & 0 & -0,5\sqrt{2} \\ 0 & 1 & 0 \\ 0,5\sqrt{2} & 0 & 0,5\sqrt{2}\end{array}\right) \)
\(= \left(\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 &1 \end{array}\right)\)
Passt also ! Und det(D)= 1.