3*22n+(3*22)n-4*22n-1+22n+2*1/4-2*(1/2)-2n=(2x)2n
Ich schreibe es mal etwas pragmatischer hin:
3*22n+(3*22)n-21*21*22n-1+ 22n+2/(21*21) -2*(1-2n/2-2n) = 22n*x2n
Potenzgesetze anwenden
3*22n+(3*22)n- 22n-1+1+1+ 22n+2-1-1 - 2*(1/2-2n) = 22n*x2n
3*22n+(3*22)n- 22n+1+ 22n - 21*22n = 22n*x2n
3*22n+(3*22)n- 22n+1+ 22n - 22n+1 = 22n*x2n
3*22n+ 3n*22n- 22n+1+ 22n - 22n+1 = 22n*x2n
3*22n+ 3n*22n- 21*22n+1+ 22n = 22n*x2n
3*22n+ 3n*22n- 22n+2+ 22n = 22n*x2n | : 22n
3+ 3n- 22+ 1 = x2n
3n = x2n | beide Seiten hoch 1/n
(3n)1/n = (x2n)1/n
3n/n = x 2n/n
x2 = 3
x 1/2 = ±√3