SIN(2·α + 2·α) = SIN(4·α)
Oder wenn man im SIN und COS nur einfache Argumente haben will.
SIN(2·α + 2·α)
= SIN(2·α)·COS(2·α) + COS(2·α)·SIN(2·α)
= 2·SIN(2·α)·COS(2·α)
= 2·(2·SIN(α)·COS(α))·(1 - 2·SIN(α)^2)
= 4·SIN(α)·COS(α)·(1 - 2·SIN(α)^2)
= 4·SIN(α)·COS(α) - 8·SIN(α)^3·COS(α)