gegeben sind: d=4 m
höhe z<ylinder= 6 m
höhe kegel = 3 m
Zylinder
V = r^2 * PI * h
V = 2^2 * PI * 6
V = 75.40 m^3
Kegel
V = r^2 * PI * h * 1/3
V = 2^2 * PI * 3 * 1/3
V = 12.57 m^3
Gesamtvolumen
75.40 + 12.57 = 87.97 m^3
Anteil Kegel in %
87.97 / 12.57 = 100 / x
x = 100 * 12.57 / 87.97