$$ \frac{1}{3} \log_2(x) + 3 \log_2(x^2) = \log_2(x^\frac{11}{6}) $$ und
$$ \log_2(x^2) + \frac{1}{2} = \log_2(\sqrt{2}x^2) $$ Daraus folgt es muss gelten
$$ x^\frac{11}{6} = \sqrt{2}x^2 $$ also $$ x^{ \frac{1}{6} } = \frac{1}{\sqrt{2}} $$ also $$ x = \frac{1}{8} $$