Wie löst man diese Gleichungen?

Question

Erste Gleichung:

a) -(x-2)²+4 = 0 

Zweite Gleichung:

b) 2,1*(x+1,6)² = 0

Answer 1

- (x - 2)^2 + 4 = 0

4 = (x - 2)^2

± 2 = x - 2

2 ± 2 = x

Comments

2.1·(x + 1.6)^2 = 0

(x + 1.6)^2 = 0

x + 1.6 = 0

x = - 1.6 (2-fache Nullstelle)

Answer 2

-(x-2)²+4 = 0

-(x-2)^2 = -4

(x-2)^2= 4

x-2 = ±2

x1= 4

x2= 0

2,1*(x+1,6)² = 0 |:2,1

(x+1,6)^2 =0

x+1,6 = 0

x = -1,6