Hallo,
Falls die Aufgabe so lautet:
f(x,y)= \( \frac{(y-4) e^{(x-17)^{5}}}{y^{2}+48} \)
\( \frac{\partial}{\partial x}\left(\frac{(y-4) e^{(x-17)^{5}}}{y^{2}+48}\right)=\frac{5 e^{(x-17)^{5}}(x-17)^{4}(y-4)}{y^{2}+48} \)
\( \frac{\partial}{\partial y}\left(\frac{(y-4) e^{(x-17)^{5}}}{y^{2}+48}\right)=\frac{e^{(x-17)^{5}}\left(-y^{2}+8 y+48\right)}{\left(y^{2}+48\right)^{2}} \)