Aloha :)
$$h(1,0,0)=\left(\begin{array}{c}0\\0\\0\end{array}\right)\quad;\quad h(0,1,0)=\left(\begin{array}{c}-1\\0\\0\end{array}\right)\quad;\quad h(1,1,0)=\left(\begin{array}{c}-1\\1\\0\end{array}\right)$$Wähe \(h\) linear, müsste gelten:$$h(1,1,0)=h(1,0,0)+h(0,1,0)=\left(\begin{array}{c}0\\0\\0\end{array}\right)+\left(\begin{array}{c}-1\\0\\0\end{array}\right)=\left(\begin{array}{c}-1\\0\\0\end{array}\right)\stackrel{!}{\ne}\left(\begin{array}{c}-1\\1\\0\end{array}\right)$$Also ist \(h\) nicht linear.