[1, 2, 1; 0, 2, 0; 1, 0, 2; 0, 3, 3]·[5, 1, 2, 0; 0, 0, 4, 2; 1, 0, 2, 1]·[0, 2, 3; 1, 0, 1; 1, 2, 0; 0, 1, 0]
= [13, 41, 19; 8, 20, 0; 7, 28, 22; 18, 51, 9]
[13, 41, 19;
8, 20, 0;
7, 28, 22;
18, 51, 9]
1 F1 benötigt also z.B. 13 E1, 8 E2, 7 E3 und 18 E4.