Prüfe mal diese Funktion
x = x1 ; y = x2
f(x, y) = - 4·x + 5·x^2 + 3·x·y - 3·y^2 - 2·x^2·y + 1·x·y^2 - 1·y^3
f'(x, y) = [2·x·(5 - 2·y) + y^2 + 3·y - 4, - 2·x^2 + x·(2·y + 3) - 3·y^2 - 6·y]
f''(x, y) = [2·(5 - 2·y), - 4·x + 2·y + 3; - 4·x + 2·y + 3, 2·x - 6·y - 6]
Jetzt noch einsetzen
f'(0, -2) = [-6, 0]
f''(0, -2) = [18, -1; -1, 6]
DET([18, -1; -1, 6]) = 107