Newton-Verfahren:
\(x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\)
Beispiel
\(x_1 = x_{0+1} = x_0 - \frac{f(x_0)}{f'(x_0)} = 2 - \frac{f(2)}{f'(2)} = 2-\frac{-3}{12} = \frac{9}{4}\)
\(x_2 = x_{1+1} = x_1 - \frac{f(x_1)}{f'(x_1)} = \frac{9}{4} - \frac{f\left(\frac{9}{4}\right)}{f'\left(\frac{9}{4}\right)} = \dots\)