a) lim x→5 \( \frac{x^2-25}{x-5} \)
x=4 \( \frac{4^2-25}{4-5} \) = \( \frac{-9}{-1} \) =9
x=4,5 \( \frac{4,5^2-25}{4,5-5} \) = 9,5
x=4,9 \( \frac{4,9^2-25}{4,9-5} \) = 9,89999999
x=4,99 \( \frac{4,99^2-25}{4,99-5} \) = 9,99
x=4,999 \( \frac{4,999^2-25}{4,999-5} \) = 9,999