Wie vorgegeben \( 1-\sqrt{x}=u \) ==> \( \sqrt{x}=u-1 \)
Und \( \frac{du}{dx} = 0,5x^{-0,5}\) ==> \( dx = -2x^{0,5} du = -2(u-1) du\)
Also \( \int \sqrt{1-\sqrt{x}} \mathrm{~d} x \)
\( = \int u^{0,5} -2(u-1) du\)
\( = -2\int (u^{1,5} - u^{0,5}) du\)
\( = -2\int u^{1,5} du +2\int u^{0,5} du\)