Hallo, kann jemand meine Aufgabe korrigieren?
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\( \begin{array}{l} \text { Nr.7) } \left.\left.\left(\begin{array}{ccc|c} 1 & 3 & 0 & 1 \\ 2 & 4 & -1 & 0 \\ 2 & 2 & -2 & 2 \end{array}\right)\right]_{i+(-2)}\right]_{+(-2)} \\ \begin{array}{l} \left(\begin{array}{ccc|c} 1 & 3 & 0 & 1 \\ 0 & -2 & 2 & -2 \\ 0 & -4 & -4 & 0 \end{array}\right) 1 \cdot(-2) \\ \left.\left(\begin{array}{ccc|c} 1 & 3 & 0 & 1 \\ 0 & -4 & -4 & 4 \\ 0 & -4 & -4 & 0 \end{array}\right)\right]+ \end{array} \\ -6+4 \\ -6+2 \\ \left(\begin{array}{ccc|c} x_{1} & x_{2} & x_{3} & 1 \\ 1 & 3 & 0 & 1 \\ 0 & 4 & -4 & 4 \\ 0 & 0 & -8 & 0 \end{array}\right) \\ \text { III. }-8 x_{3}=0 \quad 1:(-8) \\ x_{3}=0 \\ \text { II. } 4 x_{2}+(-4) \cdot 0=4 \\ \Leftrightarrow 4 x_{2}=4: 4 \\ x_{2}=1 \\ \text { I. } x_{1}+3 \cdot(1)+0 \cdot(0)=1 \\ \Leftrightarrow x_{1}+3=||-3 \\ x_{1}=-2 \\ \end{array} \)
\( \begin{array}{c} I, x_{1}+3 \cdot(1)+0(0)=1 \\ \Leftrightarrow x_{1}+3=1 \mid-3 \\ x_{1}=-2 \end{array} \)
Solsungaveisctar \( k: \vec{x}=\left(\begin{array}{c}-2 \\ 1 \\ 0\end{array}\right) \)