Maximale Ausbringungsmenge
p(x) = E(x) / x = - 0.5·x + 30 = 0
x = 60 ME
Maximaler Gewinn
G(x) = (- 0.5·x + 30)·x - (7·x + 204) = - 0.5·x^2 + 23·x - 204
G'(x) = 23 - x = 0
x = 23 ME
G(23) = - 0.5·x^2 + 23·x - 204 = 60.5 GE
p(23) = - 0.5·x + 30 = 18.5 GE