3(1-i)2 / 2(3-i)(2+i) erweitern mit (3+i)(2-i) gibt
= 3(1-i)2(3+i)(2-i) / 2(3-i)(2+i) (3+i)(2-i)
= 3 *( 1 -2i +i^2 )(3 -3i + 2i - i^2 ) / 2*(9+1)(4+1)
= 3 *( 1 -2i -1 )(3 -3i + 2i + 1 ) / 100
= 3 *( -2i )( 4 -i ) / 100
= 3*( -8i + 2i^2 ) / 100
= 3*( -8i - 2 ) / 100
= (-24i - 6 ) / 100
= -0,24i - 0,06
also Re = -0,06 Im = -0,24