G = x1·(110 - 2·x1 - x2) + x2·(280 - 5·x1 - 10·x2) - (10·x1 + 20·x2 + 100)
G = - 2·x1^2 - 6·x1·x2 + 100·x1 - 10·x2^2 + 260·x2 - 100
Gx1' = - 4·x1 - 6·x2 + 100 = 0
Gx2' = - 6·x1 - 20·x2 + 260 = 0
Löse das Gleichungssystem und erhalte x1 = 10 ∧ x2 = 10