(2x1/3)/(x2/3-3x1/3) - (x2/3)/(x5/3-x2/3) - (x+1)/(x2-4x+3)
= (2)/(x^1/3-3) - (1)/(x^3/3-1) - (x+1)/(x2-4x+3)
= (2)/(x^1/3-3) - (1)/(x-1) - (x+1)/(x2-4x+3)
. Hast du den ersten Bruch richtig abgeschrieben?
. Nebenrechnung x2-4x+3 = (x-3)(x-1)
= (2)/(x^1/3-3) - (1)/(x-1) - (x+1)/((x-3)(x-1))
= (2)/(x^1/3-3) - (x-3))/((x-1)(x-3)) - (x+1)/((x-3)(x-1))
= (2)/(x^1/3-3) - ((x-3) + (x+1))/((x-3)(x-1))
= (2)/(x^1/3-3) - (x-3 + x+1)/((x-3)(x-1))
= (2)/(x^1/3-3) - (2x - 2)/((x-3)(x-1))
= (2)/(x^1/3-3) - (2(x-1))/((x-3)(x-1))
= (2)/(x^1/3-3) - (2)/(x-3)
Bitte erst mal nachrechnen und dann diese beiden Brüche noch voneinander abziehen.