Eingesetzt:$$x_{1,2}=-\frac{-1}{2}\pm\sqrt{\left(\frac{-1}{2}\right)^2-(-6)}$$$$x_{1,2}=\frac{1}{2}\pm\sqrt{\frac{1}{4}+6}$$$$x_{1,2}=\frac{1}{2}\pm\sqrt{\frac{25}{4}}$$$$x_{1,2}=\frac{1}{2}\pm\frac{\sqrt{25}}{\sqrt{4}}$$$$x_{1,2}=\frac{1}{2}\pm\frac{5}{2}$$ Also \(x_1=3 \vee x_2=-2\)