hallo
1/(i+1) =
(i-1)/((i+1)(i-1)) =
(i-1)/(i²-1) =
(i-1)/-2 =
-(i-1)/2 =
(1-i)/2 =
1/2 - i/2
(3+4i)/(2-i) =
(3+4i)(2+i)/((2-i)(2+i)) =
(2+11i)/(4-i²) =
(2+11i)/(4-(-1)) =
(2+11i)/5 =
2/5 + 11i/5
((1+i)/(1-i))^k =
( (1+i)(1+i)/((1-i)(1+i)) )^k =
( (1 + 2i + i²)/(1-i²) )^k =
( (1 + 2i + -1)/2 )^k =
( 2i/2 )^k =
i^k
grüße