Aloha :)
Willkommen in der Mathelounge... \o/
$$f'(-2)=\lim\limits_{h\to0}\frac{f(-2+h)-f(-2)}{h}=\lim\limits_{h\to0}\frac{\left(\frac{1}{4}(-2+h)^2+8\right)-\left(\frac{1}{4}\cdot (-2)^2+8\right)}{h}$$$$\phantom{f'(-2)}=\lim\limits_{h\to0}\frac{\frac{1}{4}(4-4h+h^2)-\frac{1}{4}\cdot 4}{h}=\lim\limits_{h\to0}\frac{1-h+\frac{h^2}{4}-1}{h}=\lim\limits_{h\to0}\frac{-h+\frac{h^2}{4}}{h}$$$$\phantom{f'(-2)}=\lim\limits_{h\to0}\frac{h\left(-1+\frac{h}{4}\right)}{h}=\lim\limits_{h\to0}\left(-1+\frac{h}{4}\right)=-1$$