f ( x ) = 2/x + (1/4) * x + 3/2
A:(4|f(4))
f ( 4 ) = \( \frac{2}{4} \) + \( \frac{1}{4} \) * 4+ \( \frac{3}{2} \)=3
f´(x)=-\( \frac{2}{x^2} \)+\( \frac{1}{4} \)
A:(4|f(4))
f´(4)=-\( \frac{2}{4^2} \)+\( \frac{1}{4} \)=\( \frac{1}{8} \)
Normalensteigung : m=-8
Normalengleichung:
\( \frac{y-3}{x-4} \)=-8
y=-8x+35