3 geht so:
\( \frac{4}{3} x-3 =-\frac{1}{3} x+1 \)
<=> \( \frac{5}{3} x-3 =1 \)
<=> \( \frac{5}{3} x =4 \)
<=> \( x = \frac{12}{5} \)
Also hat S die x-Koordinate \( \frac{12}{5} \), Einsetzen
gibt \( y = \frac{1}{5} \), also S = ( \( \frac{12}{5} ; \frac{1}{5} ) \).