x-Achse heisst y =0. Also in die Gleichungen einsetzen und x berechnen
a) 3y=12x+15
0 = 12x + 15 -----> x= -15/12 = -5/4 P(-5/4 |0)
b) 4x + 5y= 5
4x = 5 → x = 5/4 P(5/4 |0)
c) x-3y=0
x=0 → P(0|0)
y-Achse heisst x=0
a) 3y=12x+15
3y = 15 → y =5 P(0|5)
b) 4x + 5y= 5
5y =5 → y=1 P(0|1)
c) x-3y=0
-3y = 0 → y = 0 P(0|0)