f(x) = x-1 / x2-1
Ich nehme an es soll so heißen
f(x) = ( x-1 ) / ( x2-1 )
u = x - 1
u ´= 1
v = x^2 - 1
v ´= 2x
( u / v ) ´= ( u´ * v - u * v ´ ) / ( x^2 - 1 )^2
[ 1 * ( x^2 - 1 ) - ( x -1 ) * 2x ] / ( x^2 -1 )^2
( x^2 - 1 - 2x^2 + 2x ) / ( x^2 -1 )^2
( - x^2 + 2x - 1 ) / ( x^2 -1 )^2
-1 * ( x^2 - 2x + 1 ) / ( x^2 -1 )^2
-1 * ( x - 1 )^2 / [ ( x -1 ) * ( x + 1) * ( x -1 ) * ( x + 1) ]
-1 / ( x + 1 )^2
einfacher
f(x) = ( x-1 ) / ( x2-1 )
f(x) = ( x-1 ) / [ ( x-1 ) * ( x + 1 )]
f ( x ) = 1 / ( x + 1 )
f ´( x ) = -1 / ( x + 1 )^2
mfg Georg