hey,
Nullstellenberechnung zu
1. (x-2)^0,5 + x-3 =0
Tipp: Subituiere z= (x-2)^0,5
2. (1 /(x^2 -1) ) + ( 2/(x^2-4) ) = 1
meine rechnung zu 2.
1. schritt: * x^2-1
1 + (2*(x^2-1)/ (x^2 -4) ) = x^2 -1
->( 2(x^2-1)/ (x^2-4) ) = x^2 -2 I * (x^2 -4)
2(x^2-1) = (x^2 -2) (x^2 -4)
2(x^2 -1) = x^4 -6x^2 +8
0= x^4 - 8x^2 + 10