Question

Gegeben sei die Funktion: f(x1, x2)=

Answer 1

df/dx1= (5.2 *x₂^{0.34})/(x₁^0.48)

df/dx2= (3.4 *x1^{0.52})/(x₂^0.66)

df =df/dx₁  *Δx1 + df/dx₂ *Δx₂

df ≈ 1.6433775

Answer 2

f(x, y) = 10·x^0.52·y^0.34

f'(x, y) = [5.2·y^0.34/x^0.48, 3.4·x^0.52/y^0.66]

f'(8, 18)·[0.35, -0.1] = 1.643375776