Abstand von S zur Geraden durch A und B
|([3, 4, 3.2] - [1, 2, 4]) ⨯ ([9, 10.5, 0.5] - [1, 2, 4])| / |[3, 4, 3.2] - [1, 2, 4]| = √210/36 = 0.4025
Oder alternativ über das Lotfußpunktverfahren
AB = B - A = [2, 2, -0.8]
PF·AB = ([1, 2, 4] + r·[2, 2, -0.8] - [9, 10.5, 0.5])·[2, 2, -0.8] = 0 → r = 895/216 = 4.144
F = [1, 2, 4] + 895/216·[2, 2, -0.8] = [1003/108, 1111/108, 37/54] = [9.287, 10.29, 0.6852]
|FS| = |[9, 10.5, 0.5] - [1003/108, 1111/108, 37/54]| = 0.4025382429