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Question

a) $3^{\frac{2}{3}} \cdot 3^{\frac{1}{3}}=$

b) $5^{\frac{1}{4}}: 5^{-\frac{1}{4}}=$

c) $2^{\frac{1}{2}} \cdot 32^{\frac{1}{2}}=$

d) $\left(\frac{2}{3}\right)^{\frac{1}{2}}:\left(\frac{2}{3}\right)^{\frac{1}{3}}=$

e) $4^{-\frac{1}{5}} \cdot 4^{\frac{3}{4}}=$

f) $\frac{2^{0,25}}{\sqrt{2}}=$

Answer 1

Hallo

a^b*a^c=a^b+c hilft bei  a,b,e

bei c): 32=2*16  und (a*b)^c=a^c*b^c

a^b: a^c=a^b-c

√a=a^1/2  0,25=1/4  für den Rest.

Gruß lul

Answer 2

a) = 3^(3/3) = 3¹ = 3

b) = 5^(1/4+1/4)= 5^(1/2) = √5

c) = 2^(1/2)*2^(5/2)= 2^(6/2) = 2³ = 8

d) = (2/3)^(1/2-1/3) = (2/3)^(3/6-2/6) = (2/3)^(1/6) = 6. Wurzel aus 2/3

e) = 4^(-4/20+15/20) = 4^(11/20) = 2^(22/20) = 2^(11/10)

f) = 2^(1/4 -1/2) = 2^(-1/4) =